In parallelogram ABCD, the diagonals intersect at point E. Find the diagonals of the parallelogram if AE = 3 dm, BE = 5 dm.

univerkov | April 4, 2021 | education

To solve the problem, we will use the property of the parallelogram diagonals. The parallelogram diagonals are halved at the intersection point. The point of intersection of the diagonals is E.
So the diagonal AC = AE + EC = 2 * AE = 2 * 3 = 6 dm.
Diagonal BD = BE + ED = 2 * BE = 2 * 5 = 10 dm.
Answer: The diagonals of the parallelogram are 6 inches and 10 inches.

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