In parallelogram ABCD, the diagonals intersect at point O. СD = 10 cm.

In parallelogram ABCD, the diagonals intersect at point O. СD = 10 cm. Find the perimeter of the parallelogram if BC / CD = AC / OC.

Since the diagonals of the parallelogram are halved at the point of their intersection, AC = 2 * OC, then AC / OC = 2 * OC / OC = 2.

Then BC / CD = AC / OC = 2.

ВС / СD = 2.

BC / 10 = 2.

BC = 2 * 10 = 20 cm.

Determine the perimeter of the parallelogram.

Ravsd = 2 * (CD + BC) = 2 (10 + 20) = 60 cm.

Answer: The perimeter of the parallelogram is 60 cm.



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