In parallelogram ABCD, the diagonals intersect at point O. Adjacent sides of the parallelogram are 10cm and 15cm.

| March 19, 2021 | education

In parallelogram ABCD, the diagonals intersect at point O. Adjacent sides of the parallelogram are 10cm and 15cm. Find the difference between the perimeters of triangle AOB and triangle AOD.

1. AB – 10 cm. AD = 15 cm.

2. The total length of all sides of the triangle AOB (perimeter) = AB + BO + AO.

3. The total length of all sides of the triangle AOD (perimeter) = AD + DO + AO.

4. BO = DO, since the diagonals BD and AC are divided by the point of intersection O into two equal segments.

With this in mind, we calculate the difference between the perimeters of these triangles:

The difference between the perimeters of the triangles AOD and AOB = 15 + ВO + AO – 10 – ВO – AO = 5 cm.

Answer: the difference between the perimeters of the triangles AOD and AOB is 5 cm.



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