In parallelogram ABCD, the height BE drawn to side AD = 12 cm, and side AC = 5 cm Find the area of parallelogram ABCD.

Given: ABCD – parallelogram; BE – the height drawn to the side AD = 12 cm; AD = 5 cm.
Find: S parallelogram.
AD = BC = 5 cm – by the property of parallel sides in a parallelogram.
In fact, the area of ​​a parallelogram is the product of the length of the height and the length of the base to which the given height is drawn.
Hence,
S parallelogram = h * a (where h is the height, a is the base to which the height is drawn, S is the area).
h in this problem is equal to 12, and the base is equal to 5. We calculate:
S = h * a = 12 * 5 = 60 (cm ^ 2) – parallelogram area.
SI area is measured in square units.
Answer: S parallelogram = 60 cm ^ 2.