In parallelogram ABCD, the height dropped to side AB is 18, sinA = 3/8. Find AD.
| May 21, 2021 | education
The parallelogram ABCD knows:
Height DK to side AB = 18;
sin A = 3/8.
Find AD.
1) Height perpendicular to side AB. A right-angled triangle ADK with right angle K is formed.
2) Consider triangle ADK.
AD – hypotenuse;
DK = leg opposite corner A.
sin A = DK / AD;
3) Find AD by the formula AD = DK / sin A.
Substitute the known values into the formula and calculate the AD side of the parallelogram ABCD.
AD = DK / sin A = 18 / (3/8) = 18 * 8/3 = 18/3 * 8 = 6 * 8 = 48.
Answer: AD = 48 m.
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