In parallelogram ABCD, the height lowered to the side of CD divides it in half and forms an angle of 30 degrees
In parallelogram ABCD, the height lowered to the side of CD divides it in half and forms an angle of 30 degrees with side BC, AB = 26 cm. Find the perimeter of the parallelogram.
It is known:
Parallelogram ABCD;
The height BK, lowered to the CD side, divides it in half;
Angle CBK = 30 °;
AB = 26 cm.
Find the perimeter of the parallelogram.
1) AB = CD = 26 cm;
CK = 1/2 * CD = 1/2 * 26 cm = 13 cm;
2) Consider a triangle СBK with a right angle K.
sin B = CK / BC;
BC = CK / sin B;
Substitute the known values and calculate the side of the ВС parallelogram.
BC = 13 / sin 30 = 13 / (1/2) = 13 * 2/1 = 13 * 2 = 26 cm;
3) Find the perimeter of the parallelogram.
P = 2 * (a + b) = 2 * (26 cm + 26 cm) = 2 * 52 cm = 2 * 50 cm + 2 * 2 cm = 100 cm + 4 cm = 104 cm.
Answer: P = 104 cm.