In parallelogram ABCD, the perpendiculars BE and DF are drawn to the diagonal AC. Prove that the BFDE is a parallelogram.

The diagonal AC of the parallelogram divides it into two equal triangles, the triangle ABC is equal to the triangle ADC.

The segments BE and DF are the heights of equal triangles, then BE = DF.

By condition, BE and DF are perpendicular to AC, then BE and DF are parallel to each other.

In the quadrangle BFDE, two opposite sides are equal and parallel, then this quadrilateral is a parallelogram, which is what we had to prove.



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