In parallelogram ABCD, the perpendiculars BE and DF are drawn to the diagonal AC.
March 10, 2021 | education
| In parallelogram ABCD, the perpendiculars BE and DF are drawn to the diagonal AC. Prove that segments BF and DE are equal.
Since ABCD is a parallelogram, then AB = CD, BC = AD, angle ABC = ADC, then triangles ABC and ADC are equal on two sides and the angle between them.
B and D are the corresponding vertices of equal triangles ABC and ADC, and the segments BE and DF are the heights drawn from the corresponding vertices, then BE = DF, which was required to prove.
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