In parallelogram ABCD, the sides are 6 cm and 8 cm, angle A = 30 degrees. Find the area of parallelogram ABCD.

1. AB = 6 cm. BC = 8 cm. Let’s designate the angle by the symbol ∠.

2. Draw a perpendicular BH to the AD side.

3. We calculate its length through the sine ∠А, equal to the quotient of dividing the ВН by AB:

ВН / AB = sinus ∠A.

ВН = AB x sine 30 ° = 6 x 1/2 = 3 cm.

4. The area of the parallelogram is equal to the product of the aircraft side length by the HВ height length:

ВС х ВН = 8 х 3 = 24 cm².

Answer: the area of the parallelogram of AVSD is 24 cm².