In rabbits, black coat color (A) dominates over white (a), shaggy coat (B) over smooth coat (b).

In rabbits, black coat color (A) dominates over white (a), shaggy coat (B) over smooth coat (b). When crossing a white smooth-haired rabbit with a black hairy rabbit in the offspring, 100% of black shaggy rabbits were obtained. Indicate the genotypes of the parents. 1) AaBb and aabb 2) AABB and aabb 3) AAbb and aaBB 4) AAbb and aabb

A white smooth-haired rabbit will be aabb according to the designations introduced in the problem statement, because homozygosity is a prerequisite for the phenotypic realization of both traits (white color and smooth coat). Such a rabbit produces the same type of spermatozoa ab and is able to transmit exclusively genes to the offspring that cause the development of recessive traits.

Since all rabbits show dominant traits, it should be concluded that the rabbit is homozygous for them, that is, her genotype does not contain recessive genes and looks like this – AABB. It produces oocytes of the same type, which contain exclusively genes for dominant traits – AB.

All rabbits produced by this pair of rabbits will be AaBb, which outwardly will be expressed in the development of their black hairy hair.

Correct answer: 2). AABB and aabb.



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