In rectangle ABCD, side AB = 3cm, BC = 4cm and point N is the middle of AB.
| June 3, 2021 | education
In rectangle ABCD, side AB = 3cm, BC = 4cm and point N is the middle of AB. find the modules of vectors: AB, BC, DC, NA, CB, AC.
The modulus of the vector a is the length of the vector a. Then:
module AB = 3 cm, module BC = CB = 4 cm.
Because ABCD is a rectangle, then AB = DC, hence the module DC = 3 cm.
Point N is the middle of AB, which means AB = NA + NB, NA = NB, AB = 2 * NA, NA = 3/2 = 1.5 cm.
∆ABS – rectangular, according to the Pythagorean theorem AC ^ 2 = AB ^ 2 + BC ^ 2.
From where: AC2 = 9 + 16 = 25, AC = 5 cm.
Answer: AB = 3 cm, BC = 4 cm, DC = 3 cm, NA = 1.5 cm, CB = 4 cm, AC = 5 cm.
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