In rectangle ABCD, the BAC angle is 35 degrees. find the angle of intersection of the diagonals.

The diagonals of the rectangle are of equal length, at the point of intersection they are divided in half, thus forming two pairs of isosceles triangles. Let’s denote by point O – the point of intersection of the diagonals.
In an isosceles triangle AOB, the base angles are equal, each 35 °. Find the angle AOB at the vertex of this triangle. The same angle will be one of the intersection angles of the diagonals.
Angle AOB = 180 ° – (35 ° + 35 °) = 180 ° – 70 ° = 110 °.
Corner AOD – Adjacent to Corner AOB.
Angle AOD = 180 ° – 110 ° = 70 °.
Answer: angles of intersection of the diagonals: 110 °, 110 °, 70 °, 70 °.