In rectangle ABCD, the diagonal BD makes an angle of 30 degrees with the side CD

In rectangle ABCD, the diagonal BD makes an angle of 30 degrees with the side CD and is equal to 22 cm. Find Sabcd.

Let’s draw a diagonal AC, which are divided in half at point O, then OD = OC = 22/2 = 11 cm.

Angle ОDА = 90 – 30 = 60. Then triangle AOD is equilateral and the angle between the diagonals is 60.

Then Savsd = (АС * ВD * Sin60) / 2 = (22 * 22 * √3 / 2) / 2 = 121 * √3 cm2.

Answer: The area of the rectangle is 121 * √3 cm2.



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