In rectangle ABCD, the diagonals AC and BD intersect at point O. Angle AOD = 112 degrees.

In rectangle ABCD, the diagonals AC and BD intersect at point O. Angle AOD = 112 degrees. Find the corners of the triangle COD.

1. Calculate the value of the COD angle adjacent to the AOD angle:

COD angle = 180 ° – 112 ° = 68 °.

2. The diagonals of the rectangle are equal to each other and are halved at the point of intersection.

Therefore, the triangle COD is isosceles. This means that the angles at the base of the CD of this triangle are equal. We calculate their value:

Angle DСО = angle ОDС = (180 ° – 68 °) / 2 = 56 °.

Answer: Angle DCO is 56 °, Angle ODC is equal, Angle COD is 68 °.