In rectangle ABCD, the diagonals intersect at point O, AB = 9cm, AC = 16cm. Find the perimeter of the COD triangle.

Given:
rectangle ABCD,
diagonals AC and BD intersect at point O,
AB = 9 centimeters,
AC = 16 centimeters.
Find the perimeter of the triangle COD -?
Decision:
1) Consider a rectangle ABCD. His opposite sides are equal to each other, then BC = AD, AB = CD = 9 centimeters. The diagonals in the rectangle are equal to each other, that is, AC = BD = 16 centimeters and the intersection point is divided in half, then BO = OD = AO = OS = 16: 2 = 8 (centimeters).
2) The perimeter of the triangle COD, that is, P COD = CD + DO + OC = 8 + 8 + 9 = 25 (centimeters).
Answer: 25 centimeters.