In rectangle ABCD, the diagonals meet at point O, AB = 9 cm, AC = 16 cm. Find the perimeter of triangle COD.

univerkov | December 21, 2020 | education

1) Because AВСD is a rectangle, then AC = ВD = 16 cm. And since the diagonals are divided in half by the point of intersection, then BO = OD = OС = OA; AB = 9cm
2) OS = 16: 2 = 8cm
OD = OС = 8 cm
Because AВСD is a rectangle, then AB = СD by property
3) Perimeter of triangle COD = OD + СD + OС
Perimeter COD = 8 + 8 + 9 = 25cm
Answer: 25 cm

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