In rectangular Δ ABC (LC = 90 degrees) AE-bisector CE = 5cm, AB = 14cm, find the area of Δ ABE.

Since AE is the median of the triangle ABC, then by its property:

AC / CE = AB / EB.

AC * BE = CE * AB = 5 * 14 = 70 cm2.

The leg AC is the height of the triangle ABE, then Save = BE * AC / 2 = 70/2 = 45 cm2.

Answer: The area of triangle ABE is 45 cm2.



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