In rectangular parallelepiped ABCDA1B1C1D1 it is known that BD1 = 27 BB1 = 2√26 AB = 24 Find the length AD.

At the base of a rectangular parallelepiped is a rectangle. Let us draw the diagonal BD at the base and determine its length according to the Pythagorean theorem from the right-angled triangle BD1D.

DD1 = BB1 = 2 * √26 cm, then:

BD ^ 2 = BD1 ^ 2 – DD1 ^ 2 = 27 ^ 2 – (2 * √26) ^ 2 = 729 – 104 = 625.

ВD = 25 cm.

From the right-angled triangle ABD we determine the length of the leg AD.

AD ^ 2 = BD ^ 2 – AB ^ 2 = 25 ^ 2 – 24 ^ 2 = 625 – 576 = 49.

AD = 7 cm.

Second way.

The square of the diagonal of a rectangular parallelepiped is equal to the sum of the squares of the lengths of its sides.

BD1 ^ 2 = AB ^ 2 + BB1 ^ 2 + AD ^ 2.

AD ^ 2 = BD1 ^ 2 – AB ^ 2 – BB1 ^ 2 = 729 – 576 – 104 = 49.

AD = 7 cm.

Answer: The length of the BP side is 7 cm.



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