In rhombus ABCD, angle A = 142 degrees. Find the value of the angle adjacent to the inner angle B.

Since, by the property of a rhombus, two adjacent angles add up to 180 °, and in this rhombus ABCD ∠A = 142 °, then:

∠A + ∠В = 180 °;

142 ° + ∠В = 180 °;

∠В = 180 ° – 142 °;

∠В = 38 °.

The sum of adjacent angles is 180 °. Since the inner angle of the rhombus ABCD ∠В = 38 °, the outer angle, which is adjacent to the inner ∠В, is equal to 142 °.