In rhombus ABCD is the O-point of intersection of the diagonals. Find the angles of the rhombus

In rhombus ABCD is the O-point of intersection of the diagonals. Find the angles of the rhombus of triangle AOB if one of the rhombus angles is 110 °.

The sum of the adjacent angles of the rhombus is 1800, then the angle BAD + ABC = 180.

ВAD = 180 – ABC = 180 – 110 = 70.

The diagonals of the rhombus divide the angle at the apex in half, then the angle ABO = ABC / 2 = 110/2 = 550, and the angle BAO = ВAD / 2 = 70/2 = 35.

The diagonals of the rhombus intersect at right angles, then the angle AOB = 90.

Answer: The angles of the AOB triangle are 35, 55, 90.



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