In rhombus ABCD, the ADC angle is 150 degrees. Find the value of the angle BAC.

Consider a triangle ACD:

1) The sum of all angles in a triangle is 180 °, therefore the angles CAD and ACD account for: 180 ° – 150 ° = 30 °;

2) 30 °: 2 = 15 ° – CAD angle and ACD angle separately;

3) Triangles ABC and ACD are equal, hence the angle BAC = CAD = 15 °;

ANSWER: 15 °



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