In rhombus ABCD, the angle ACB is 65 degrees, find the angle CDA.

The diagonals of the rhombus are the bisectors of the angles at its vertices, then the angle ВСD = 2 * АСВ = 2 * 65 = 130.

The sum of the adjacent angles of the rhombus is 180, then the angle CDA + BCD = 180.

Angle CDA = 180 – BCD = 180 – 130 = 50.

Answer: Angle CDA = 50.



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