In rhombus ABCD, the DAB angle is 36º. Find the DBC corner.

We need to define the DBC angle.
First, let’s find the angle ABC.

It is known that opposite angles in a rhombus are equal (by property).
Hence it follows that ∠DAB = ∠DCB = 36 °.

Also, since the rhombus is a quadrangle, the sum of all its angles is 360 °.
This means that the sum of the angles ABC and ADC is equal to:
360 ° – (∠DAB + ∠DCB) = 360 ° – (36 ° + 36 °) = 360 ° – 72 ° = 288 °.

Therefore, ∠ABC = ∠ADC = 288 ° / 2 = 144 °.

Since DB is a diagonal, then, by the property of the rhombus, it divides the angle ABC in half.
Hence ∠DBC = ∠ABC / 2 = 144 ° / 2 = 72 °.
Answer: ∠DBC = 72 °.