In rhombus ABCD, the height BK is drawn, which divides the side AD into segments AK = 9 cm, KD = 9 cm.

In rhombus ABCD, the height BK is drawn, which divides the side AD into segments AK = 9 cm, KD = 9 cm. Find the corners of the diamond.

Since the height BK of the trapezoid divides the side of the rhombus into equal segments, this height is also the median of the triangle ABD.

If the median of a triangle coincides with its height, then such a triangle is equilateral, which means that its interior angles are 60.

Then the angle BAD = ABD = ADB = 60. Since the diagonal of the rhombus BD divides the angle ADC in half, the angle ADC = 2 * ADB = 2 * 60 = 120.

Answer: The angles of the rhombus are 60 and 120.