In rhombus ABCD, where O is the intersection of the diagonals BD and AC, the angle BAD is 80.

In rhombus ABCD, where O is the intersection of the diagonals BD and AC, the angle BAD is 80. Find the corners of the triangle COD.

In order to solve this problem, you need to know all the properties of the rhombus and carefully study the condition of the problem. Angle ADC = 180 – 80 = 100 °. The diagonals of a rhombus are the bisectors of its corners. Hence the angle ODC = 100/2 = 50 °, the angle DCO = 80/2 = 40 °.

Since the diagonals of the rhombus intersect at right angles, the angle COD = 90 °.

Therefore our answer is 90 °.