In rhombus MPKH, the diagonals meet at point O. one of the corners of the triangle PKO
| September 3, 2021 | education
In rhombus MPKH, the diagonals meet at point O. one of the corners of the triangle PKO is 33 degrees. find the angles PKO and PMH.
Since the diagonals in the rhombus are the bisectors of its corners, then:
Option 1: ∠PKO = 33.
∠PKH = 2 * ∠PKO = 2 * 33 = 66 degrees.
Since the angles of the rhombus are pairwise equal:
∠PMH = ∠PKH = 66 degrees.
Option 2: ∠PKO = 90 – 33 = 56.
∠PKH = 2 * ∠PKO = 2 * 56 = 112.
∠PMH = ∠PKH = 112.
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