In rhombus MPKH, the diagonals meet at point O. One of the corners of the triangle PKO is 33 degrees. find the angles of this triangle PKO and triangle PMH.
Since the diagonals in the rhombus intersect at an angle of 90 degrees, the PKO triangle is rectangular, then its 2nd angle is:
180 – 90 – 33 = 66 degrees.
Since the diagonal of the rhombus divides it into two isosceles triangles, the PMH triangle will be isosceles,
two angles in which the wound is 33 degrees. Then the 3rd angle will be equal to:
180 – 2 * 33 = 114 degrees.
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