In right-angled triangle ABC, angle C is 90, angle B is 25 Find the angle between the height

In right-angled triangle ABC, angle C is 90, angle B is 25 Find the angle between the height of the triangle CH and the bisector CL.

Since CH is the height, then the triangle BCH is rectangular, then the angle BCH = 180 – СНВ = СВН = 180 – 90 – 25 = 65.

Since the angle С = 90, and the segment ОL is the bisector of the angle С, then the angle ВСL = 90/2 = 45.

Determine the value of the HCL angle.

Angle HCL = BCH – BCL = 65 – 45 = 20.

Answer: The HCL angle is 20.



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