In right-angled triangle abc with right angle C and A = 50 degrees, the height CD is drawn. Find the angle BCD.

To find <BCD, define the value <ABC (that is, <B).

The degree sum of the angles of any triangle is 180 degrees.

In a triangle ABC <C = 90 – by condition, <A = 50 – by condition, therefore <ABC = 180 – 90 – 50 = 40 degrees.

Since CD is the height of triangle ABC, then <CDB = 90, then, based on the sum of the angles of the triangle: <BCD = 180 – 90 – <ABC = 90 – 40 = 50 degrees.

Answer: <BCD = 50 degrees.



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