In sugar cane, the mass fraction of sucrose is 20% on average. Calculate how much fructose

In sugar cane, the mass fraction of sucrose is 20% on average. Calculate how much fructose can be obtained from a cane weighing 25 tons?

1 ton – 20%,

25 t – x%,

x = (25 t × 20%): 1 t = 5 t.

Let’s find the amount of sucrose substance.

M (C12H22O11) = 342 kg / kmol.

n = 5000 kg: 342 kg / kmol = 14.62 kmol.

C12H22O11 + H2O = C6H12O6 + C6H12O6.

For 1 mol of С12Н22О11, there is 1 mol of С6Н12О6.

Substances are in quantitative ratios 1: 1.

The amount of substance is equal.

n (C6H12O6) = n (C12H22O11) = 14.62 kmol.

Let’s find the mass of С6Н12О6.

M (C6H12O6) = 180 kg / kmol.

m = n × M.

m = 180 kg / kmol × 14.62 kg / kmol = 2631.6 t.

Answer: 2631.6 t.