In the ABC triangle, the AB side is 12 dm, and the CK height is 18 dm. find the area of the triangle ABC.

The area of a triangle is equal to half the product of the base by the height drawn to this base. We have a triangle ABC with base AB and height CK. Base AB = 12 dm, height CK = 18 dm. In this case, S = 1/2 * AB * CK.

S = 1/2 * 12 * 18 = 108 dm.

Answer: S = 108 dm.

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