In the ABC triangle, the AB side is 12 dm, and the CK height is 18 dm. find the area of the triangle ABC.
| July 25, 2021 | education
The area of a triangle is equal to half the product of the base by the height drawn to this base. We have a triangle ABC with base AB and height CK. Base AB = 12 dm, height CK = 18 dm. In this case, S = 1/2 * AB * CK.
S = 1/2 * 12 * 18 = 108 dm.
Answer: S = 108 dm.
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