In the ABC triangle, the AB side is 40 cm, which is 4/5 of the BC side, and the AC

In the ABC triangle, the AB side is 40 cm, which is 4/5 of the BC side, and the AC side is 2.3 inches less than the BC side. Find the perimeter of triangle ABC and express it in meters.

By the condition of the problem, a triangle ABC is given.

It is known that the length of the AB side is 40 centimeters.

Let’s calculate what the length of the BC side is, taking into account that the AC is 4/5 of the BC:

40/4/5 = 40 * 5/4 = 200/4 = 50 centimeters.

Let’s determine the length of the AC side, which is 2.3 decimeters less than the BC side:

2.3 dm = 23 cm.

50 – 23 = 27 centimeters.

Find the perimeter of the triangle:

P = 40 + 50 + 27 = 117 cm.

Let’s express the perimeter in meters:

117 cm = 1.17 m.

Answer: The perimeter of triangle ABC is 1.17 meters.