In the ABC triangle, the angle A = 76 degrees, the outer angle at the vertex B is 94 degrees. Find the corner C.

Let us determine the value of the adjacent angle ABC with the external angle ABC. Angle ABC = (180 – ABK) =) 180 – 94) = 86.

Then in the triangle ABC the angle ACB = (180 – ABC – BAC) = (180 – 86 – 76) = 18.

Answer: The ACB angle is 18.



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