In the ABC triangle, the angle c is 90 BC = 6, cosA = (1 / √5). Find AC.

univerkov | August 23, 2021 | education

We define the tangent of this angle through the cosine of the angle.

tg2BAC = (1 / Cos2BAC) – 1 = (1/1/5) – 1 = 4.

tgBAC = 2.

Then tgBAC = BC / AC.

АС = ВС / tgВАС = 6/2 = 3 cm.

Answer: The length of the AC leg is 3 cm.

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