In the ABC triangle, the angle C is 90, CH is the height, AB = 15, cos A = 0.6. Find AH.

In a right-angled triangle ABC CosA = AC / AB.

AC = AB * CosA = 15 * 0.6 = 9 cm.

Let’s define SinA. Sin2A = 1 – Cos2A = 1 – 0.36 = 0.64.

SinA = 0.8 then SinA = CH / AC.

CH = AC * SinA = 9 * 0.8 = 7.2.

In a right-angled triangle ACN, according to the Pythagorean theorem, AH ^ 2 = AC ^ 2 – CH ^ 2 = 81 – 51.84 = 29.16.

AH = 5.4 cm.

Answer: The length of the segment AH is 5.4 cm.



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