In the ABC triangle, the angle is C = 40 degrees, the outer angle at the vertex

In the ABC triangle, the angle is C = 40 degrees, the outer angle at the vertex is B = 70 degrees. Find the rest of the interior corners of the triangle.

The outer corner of a triangle is equal to the sum of its two inner angles that are not adjacent to it.

Angle ABM = (ACB + BAC).

70 = (40 + BAC).

Angle BAC = (70 – 40) = 300

Then the angle ABC = (180 – 30 – 40) = 110.



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