In the ABC triangle, the angle is C = 90 degrees, AC = 5, cosA = 24/25. Find the height CH.

Define the sius of the СAН angle.

Sin2CAH = 1 – CosCAH = 1 – 576/625 = 49/625.

SinCAH = 7/25.

Then SinCAH = CH / AC.

H = AC * SinCAH = 5 * 7/25 = 35/25 = 1.4 cm.

Answer: The length of the CH height is 1.4 cm.



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