In the ABC triangle, the sides AB and BC have the same ragged length of 5 dm, and the sides of the AC are 2 dm

In the ABC triangle, the sides AB and BC have the same ragged length of 5 dm, and the sides of the AC are 2 dm shorter than each of them. Calculate the perimeter of the triangle ABC.

Since the AC side is 2 inches shorter on either of the other two sides, then its length is:

5 – 2 = 3 dm.

By definition of the perimeter, the perimeter of a triangle is equal to the sum of its sides:

AB + AC + BC = 5 + 5 + 2 = 12 dm.

Answer: the desired perimeter of triangle ABC is 12 dm.



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