In the acid obtained by dissolving 11.2 l of gaseous hydrogen chloride in water, 13 g of zinc were placed.

In the acid obtained by dissolving 11.2 l of gaseous hydrogen chloride in water, 13 g of zinc were placed. Calculate the amount of gas released during this.

When dissolved in hydrochloric acid, metallic zinc is converted to zinc chloride. Zinc is a divalent metal. Therefore, during the reaction, it interacts with double the amount of hydrogen chloride. This synthesizes a single chemical amount of zinc chloride. The reaction is described by the following chemical reaction equation:

Zn + 2HCl = ZnCl2 + H2;

Let’s calculate the molar amount of hydrogen chloride. To do this, we divide its volume by the volume of 1 mole of gas.

N HCl = 11.2 / 22.4 = 0.5 mol;

Let’s calculate the chemical amount of zinc. For this purpose, we divide its weight by the mass of 1 mole of metal.

N Zn = 13/65 = 0.2 mol;

With this amount of zinc, 0.4 mol of acid will react. This will synthesize 0.2 mol of hydrogen. Let’s find its volume. To do this, multiply the amount of substance by the volume of 1 mole of gas (22.4 liters).

V H2 = 0.2 x 22.4 = 4.48 liters;