In the calorimeter there is a liquid weighing 100 g at a temperature of 25 ° C. A 100 g ball with a temperature of 75 ° C

In the calorimeter there is a liquid weighing 100 g at a temperature of 25 ° C. A 100 g ball with a temperature of 75 ° C was lowered into it. After that, a temperature of 30 ° C was set in the calorimeter. How many times the specific heat capacity of the liquid is greater than the specific heat capacity of the ball material.

Given:
m1 = 100g = 0.1kg,
m2 = 100g = 0.1kg,
t1 = 25 ° С,
t2 = 75 ° C;
t = 30 ° C;
Find: с1 / с2 -?
Let’s write the heat balance equation:
Q1 = Q2,
where
Q1 = m1 * c1 * (t – t1) – heat received by the liquid,
Q2 = m2 * c2 * (t2 – t) – heat given off by the ball;
We get:
m1 * c1 * (t – t1) = m2 * c2 * (t2 – t);
c1 / c2 = [m2 * (t2 – t)] / [m1 * (t – t1) = 50/5 = 10.