In the calorimeter there was a liquid weighing 100 g at a temperature of 25, a ball with a mass of 100 g was lowered into it, the temperature of which was 75C. After that, the temperature in the colorimeter was set at 30C. How many times is the specific heat capacity of the liquid greater than the specific heat of the ball material?
Before solving the problem, it is necessary to remember the basics of thermodynamics and the law of conservation of energy:
1) Q expended = Q received
2) The body with more energy gives it to the body with less energy until equilibrium is established.
It is also worth remembering the following formula: Q = c * m * (deltaT)
Since the mass is the same, you can forget about it.
Solution (writing in a notebook):
Qsatr. = Qreceive.
c1 * m * (deltaT1) = c2 * m * (deltaT2)
c1 / c2 = (deltaT2) / (deltaT1)
s1 / s2 = 45/5 = 9
Answer: c1 / c2 = 9
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