In the circle AB and CD – two not mutually perpendicular diameters, DE perpendicular to AB
| July 18, 2021 | education
In the circle AB and CD – two not mutually perpendicular diameters, DE perpendicular to AB, CD = 4, DE = √3. Find an acute angle between the diameter and.
Consider a DOE triangle.
The triangle is rectangular, since the DEO angle is a straight line by condition.
DO = ½ DC = ½ * 4 = 2.
sin∠DOE = DE / DO = √3 / 2.
∠DOE = 60 °.
Answer: the acute angle between the diameters is 60 °.
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