In the circuit shown in the figure, the voltage at the terminals of the battery U is 1000V, R1 = 100 Ohm, R2 = 200 Ohm

In the circuit shown in the figure, the voltage at the terminals of the battery U is 1000V, R1 = 100 Ohm, R2 = 200 Ohm, R3 = 300 Ohm. What voltage does the voltmeter show if its resistance R = 2000 ohms.

Resistances R2 and R3 are connected in series, then R23 = R2 + R3 = 200 + 300 = 500 ohms.

Resistance R23 and the resistance of the voltmeter are connected in parallel, then:

R4 = Rv * R23 / Rv + R23 = 2000 * 500/2500 = 400 ohms.

Then the resistance of the circuit is equal to:

Rob = R4 + R1 = 400 + 100 = 500 Ohm.

Determine the current flowing through the resistance R1.

I = E / Rob = 1000/500 = 2 A.

Determine the voltage drop across the resistor R1.

U1 = I * R1 = 2 * 100 = 200 B.

Then the voltmeter readings are equal: U = E – U1 = 1000 – 200 = 800 V.

Answer: The voltmeter will show 800 V.



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