In the circuit shown in the figure, the voltage at the terminals of the battery U is 1000V, R1 = 100 Ohm, R2 = 200 Ohm
In the circuit shown in the figure, the voltage at the terminals of the battery U is 1000V, R1 = 100 Ohm, R2 = 200 Ohm, R3 = 300 Ohm. What voltage does the voltmeter show if its resistance R = 2000 ohms.
Resistances R2 and R3 are connected in series, then R23 = R2 + R3 = 200 + 300 = 500 ohms.
Resistance R23 and the resistance of the voltmeter are connected in parallel, then:
R4 = Rv * R23 / Rv + R23 = 2000 * 500/2500 = 400 ohms.
Then the resistance of the circuit is equal to:
Rob = R4 + R1 = 400 + 100 = 500 Ohm.
Determine the current flowing through the resistance R1.
I = E / Rob = 1000/500 = 2 A.
Determine the voltage drop across the resistor R1.
U1 = I * R1 = 2 * 100 = 200 B.
Then the voltmeter readings are equal: U = E – U1 = 1000 – 200 = 800 V.
Answer: The voltmeter will show 800 V.