In the conductor, in 10 s, an amount of heat was released equal to 4050 J

In the conductor, in 10 s, an amount of heat was released equal to 4050 J. the voltage at the ends is 45 V. find the amperage in the conductor.

To find the current in the specified conductor, you must use the formula: Q = U * I * t (Joule-Lenz law), from where we express: I = Q / (t * U).

Variables: Q – released heat (Q = 4050 J); t – elapsed time (t = 10 s); U is the voltage at the ends of the specified conductor (U = 45 V).

Calculation: I = Q / (U * t) = 4050 / (10 * 45) = 9 A.

Answer: A current of 9 A flows through the indicated conductor.