In the cylinder under the piston with an area of S = 100 cm2 there is nitrogen, m = 28g

In the cylinder under the piston with an area of S = 100 cm2 there is nitrogen, m = 28g at a temperature of t1 = 100 degrees Celsius. A load of M = 50 kg is supplied to the piston through a system of blocks. The cylinder is cooled down to t2 = 0 degrees Celsius. To what height Delta h will the load rise? Disregard the mass of the piston.

The mass of one mole of nitrogen N2: MN2 = 0.014 * 2 = 0.028 kg / mol.

Gas mass mg = 0.028 kg.

Amount of substance: v = mg / MN2 = 0.028 kg / 0.028 kg / mol = 1 mol.

Load pressure Pm:

PM = Mg / S,

where Mg is the weight of the cargo,

S is the area of the piston.

Gas pressure P and load pressure PM (upward) are balanced by atmospheric pressure Pa:

P + PM = Pa;

P + Mg / S = Pa;

P = Pa – Mg / S = 10 ^ 5 Pa – (50 kg * 10 m / s2) / 0.01 m2 = 5 * 10 ^ 4 Pa.

The process is isobaric.

Answer: 1.66 m.