In the equilateral triangle ABC, the median BK is drawn. Determine the angles of the triangle СBK.

In an equilateral triangle ABC, all angles are equal to 60 degrees:
It is necessary to define the angles <BKC, <KBC, <BCK.
<BCA = <BCA = 60 gr.
In an equilateral triangle, the medians and bisectors coincide, that is, BK divides <ABC in half:
<KBC = 60/2 = 30 gr.
The medians and heights also coincide, i.e. <CKB – direct:
<CKB = 90 gr.
Answer: 30 gr., 60 gr., 90 gr.



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