In the first 3 hours, the pedestrian walked 12 km. For the next 2 hours he walked at a speed of 3 km / h.

In the first 3 hours, the pedestrian walked 12 km. For the next 2 hours he walked at a speed of 3 km / h. Determine the speed of the pedestrian along the way.

1) First, let’s find a path on the second section:
S = V * T = 3 * 2 = 6km
2) Vcp = SBce / TBce
3) Find all the way and all the time:
Sweight = S1 + S2 = 12 + 6 = 18km
TBce = T1 + T2 = 3 + 2 = 5 h
Find Vcp:
Vcp = 18/5 = 3.6 km / h



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