In the first hour, the student completed 1/2 of the task, in the second – 0.6 of the remaining task.

In the first hour, the student completed 1/2 of the task, in the second – 0.6 of the remaining task. How many times is the part completed in the first hour, more than the part completed in the second hour?

Let’s take the whole task as x. Then, in the first hour, the student completed 1/2 x assignments, and in the second – 0.6 * (x-1/2 x) assignments.
(1/2 x) / (0.6 * (x-1/2 x)) = (1/2 x) / (0.3 x) = 10 / (2 * 3) = 5/3.
Answer: the part of the work in the first hour is 5/3 times more than the part in the second hour.