# In the first second of its fall without initial velocity, the body covered 1/36 of the entire path. How many seconds did the body fall?

January 16, 2021 | education

| 1) Let us calculate the height from which this body fell (we assume that the fall of this body was free):

S1 = h = a * t1 ^ 2/2, where S1 is the distance that the body will cover in the first second of the fall (S1 = 1/36 S), and is the Acceleration with which the body fell (a = g = 10 m / s ^ 2), t1 is the fall time (t1 = 1 s).

1/36 S = g * t ^ 2/2.

S = 18g * t ^ 2 = 180 * 10 * 1 ^ 2 = 180 m.

2) Let’s calculate the fall time:

S = g * t ^ 2/2; t ^ 2 = 2S / g; t = √ (2S / g).

t = √ (2 * 180/10) = √36 = 6 s.

Answer: This body fell for 6 seconds.

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