In the first second of uniformly accelerated motion without an initial velocity, the body passed 2 m.

In the first second of uniformly accelerated motion without an initial velocity, the body passed 2 m. What distance did it cover in the first 4 s.

Given:

S = 2 meters – the path covered by the body in the first second of uniformly accelerated motion;

t1 = 4 seconds – time span.

It is required to determine S1 (meter) – the path traveled by the body during the time interval t1.

Since, according to the condition of the problem, the body moves without initial velocity, we find the acceleration with which the body moves:

S = a * t2 ^ / 2, where t = 1 second;

a = 2 * S / t ^ 2 = 2 * 2/1 ^ 2 = 4 m / s2.

Then in 4 seconds the body will cover the path:

S1 = a * t1 ^ 2/2 = 4 * 4 ^ 2/2 = 2 * 4 ^ 2 = 2 * 16 = 32 meters.

Answer: in the first 4 seconds of movement, the body will cover a distance of 32 meters.